Like the title says, how can I filter with grep (or similar bash tool) the line-before-the-last-line of a (variable length) file?
I am trying to write a bash script which will search through a txt file for a string from another txt file which is stored within a variable.However the string has a number of special characters in it
I have many (near 100) big csv files with sellID in first column. I know that some sellID are repeated 2 or more times in 2 or more files. Is possible with grep find a开发者_运维知识库ll this duplicat
$ wget --output-document=/dev/null http://website.com/file.jpg Resolving speedtest.sea01.softlayer.com... 67.228.112.250
I run git grep \"\\<blah\\>\" regularly on my linux development server, but I just discovered that I am not able to use \\< and \\> on Mac (Mac OS X 10.6.8) (not able to use = it does not
I need to check several files which are in different locations for a specific informat开发者_StackOverflowion.
Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow.
I am trying to subtract List_1 (50k lines) from List_2 (100k lines) , when an item in List_1 is an exact match for an item in List_2. I am using grep, specifically:
How can I list every occurrence of a regex in a file, where one line can contain the regex multiple times?
I\'m writing a bash script and one of the tasks which needs performing is to connec开发者_运维技巧t to an FTP server via curl and find the name of the last modified .zip file.
加载中,请稍侯......