I have this code: #include <stdio.h> int getAns(void); int num; int main() { int (*current_ans)(void);
Currently the below code gives me a wa开发者_如何学Pythonrning when i try to compile it: int z; char *w;
int *w; int **d; d = &w; What does the **d store exa开发者_如何学JAVActly?After the assignment, **d is the same as *w.d is a pointer to a pointer to an integer; the pointer to an integer that i
I know about all about pointers and the ampersand means \"address of\" but what\'s it mean in this situation?
I\'m trying to have pointer to class methods, so I have something like: class foo { public: static void bar() {
The code is char** p = (char **) malloc(sizeof(char **) * size); //Where size is some valid value. p[1] = (char*) malloc(sizeof(char) * 30);
I was wondering if it is possible to traverse a linked开发者_Python百科 list like this: currentNode = randomNode;//where randomNode may or may not = firstNode
I have a superclass and a subclass, both of which define instance variables. 开发者_Go百科 Rough outline of superclass:
If I have a list<object*>>* queue and want to pop the first object in the list and hand it over to another part of the program, is it correct to use (sketchy code):
If I understand slicing correctly I don\'t think this could happen with pointers or smart pointers. For example, if you had:
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