?- assert(p(a)),assert(p(b)),p(X). X = a yes Wha开发者_如何学运维ts the effect of this query and why does it return this particular result?It is as if you queried the following source:
Using Allegrograph, Prolog functors are pretty awesome, but there is one downside. Let\'s say you define a functor that links two entities, for example parentOf which equals to \"!n:motherOf OR !n:f
How would I write the following in Prolog?开发者_JAVA技巧 a -> b V c In English that would be a implies that b or c (or both)The clause
I\'m trying to keep my Prolog code modular, and I was wondering if anyone had any advice as to how to do this. The way I was doing this with simple consults, but that is getting cumbersome as the numb
I am trying to use JPL for the interaction of Java programs and YAP Prolog. In my java file, this line is throwing an exception:
In this link ( Meta Interpreter ) I believe to have found a nifty way of solving a problem I have to tackle, but since my prolog is very bad I\'d first ask if its even possible what I have in mind.
I am newbie to prolog and I am trying to flatten a list which is like this: X = [[[0,0,1],[1,0,2]],[[0,1,3],[0,2,2]],[[0,3,5],[0,4,4]],[[0,5,4],[0,6,5]]]
From what I understand, in Prolog you capture features while parsing 开发者_JS百科like so: foo(feature(X)) --> [X], bar.
I\'ve got the following diagram given: Diagram here The first gateway/connector is an OR-gateway/connector (it has a circle in it). The gateway/connector with a \'x\' in it is a XOR-gateway/connecto
I am new to Prolog. I am writing Prolog code to solve a puzzle which requires me to find duplicates in a 2 dimensional grid of numbers.
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