This question already has answers here: How can I prevent SQL injection in PHP? (27 answers) Closed 2 years ago.
$mysql_connection = new mysqli(blah blah blah.. $query = \"SELECT * FROM posts ORDER BY id DESC\"; $result = $mysql_connection->query($query);
I am trying to update my table t1 which has rows as following :- id menu Currently i am having data in it as
I use a specific que开发者_如何学Cry that is acting weird: On my local environment, it works perfect and sends no warning. Online, the query itself works fine, however, mysqli_fetch_assoc($result) is
My idea is simple: if child->indent, if parent->make bold. Lets say p0 is the parent of p1 and p2, p3 and p4 are the childs of p1. p5 is the independent page like p0. So what i wanna get is
How php/mysqli ( with prepared statements + bind params ) protect against SQL Injection ? Mysqli applies only \"real_escape_string\" for variables or do something else?
I\'m working on dreamviewer. When i\'m trying to write basic syntax it usually autocompletes. As you see it offers 2 variants for "escape&开发者_开发技巧quot;: real_escape_string and escape_stri
I am trying to convert my current code to MySQLi extension... But I have a problem with this code.. $sql = \"SELECT COUNT(*) FROM users WHERE username=\'$username\'\";
I have read this post and i开发者_StackOverflowt didn\'t really help. My php.ini file (http://www.edisk.cz/stahni/09234/php.ini_69.47KB.html) contains the correct path of ext directory.
For some weird reason, the following code is returning null, while the manual states it should either return true or false. There is also no information in the mysqli object.
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