Sorry for as开发者_如何转开发king silly question Is it possible to enforce constraint on generic in such a way that the given T can be derived
Recently I ha开发者_Python百科ve read a term \"naked type constraint\" in the context of Generics. What does it
Say I\'d li开发者_开发技巧ke to implement something like this: def serialize( list: List[_] ) : Node = {
This code: println(new XStream.toXML(List(1,2,3))) produces this XML: <scala.coloncolon serialization=\"custom\">
Given the following models adapted from http://www.djangoproject.com/documentation/models/generic_relations/
In this code: TTest<IntfT: IInterface> = class protected fObj : TInterfacedObject; public functionGetVal: IntfT;
Following on from another question I asked, Scala 2.8 breakout, I wanted to understand a bit more about the Scala method TraversableLike[A].map whose signature is as follows:
public class StuffDoer<T> { // do stuff } I want that this is always of type string, so instead of doing this:
public class CollectionsFilter { public static void main(String[] args) { List<Integer> list = Arrays.asList(new Integer[] { 1, 2, 3, 4, 5, 6, 7,
Is it possible to Deserialize the following piece of XML into a Dictionary<int,string> object? XML:
加载中,请稍侯......