When a function returns, is the memory allocated via malloc freed? Or can it still be accessed in the main() function using pointers?
In the following code,what is the meaning ofbuf = malloc(n * sizeof(char)); is n*sizeof(char) necessary,if yes.. please elaborate.
I need to allocate, and free lots of fixed size, small (16 byte) blocks of memory, in no fixed order.I could just call malloc and free for each, but that will probably be very inefficient.A better sol
typedef struct _DListNode { struct _DListNode* prev; struct _DListNode* next; void*data; }DListNode; in gcc :
I am allocating memory in a C program using malloc. It\'s possible for my program to allocate more memory than the system has room for, at which point the program crashes. For my purposes it would be
This question already has answers here: Closed 12 years ago. Possible Duplicate: c difference between malloc and calloc
This question already has answers here: 开发者_Go百科How do malloc() and free() work? (13 answers)
I have a malloc in C that is 26901^2*sizeof(double) This got me thinking what the largest value can be here?
This question already has answers here: Closed 12 years ago. Possible Duplicates: Do I cast the result of malloc?
I wrote the following example program but it crashes with segfault. The problem seems to be with using malloc and std::strings in the structure.
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