This is the example code, I\'m using these functions for a program, but scanf doesn\'t work well: It doesn\'t display my input and accepts the input only after the enter key is pressed twice.
In this code, scanf works only 开发者_高级运维once. What am I doing wrong? #include <stdio.h>
I\'m reading MAC addresses (in standard hex notation, e.g. 00:11:22:33:44:55) from stdin and converting them into a 6 byte variable hw_addr as decimals:
I have a situation here i am taking input fro开发者_StackOverflowm user using scanfcan I terminate the scanf as soon as user presses the # key
Why does this not work as expected? int main() { unsigned char louise, peter; printf(\"Age of Louise: \");
This is my C code that reads a list of URLs from a file, and tries to separate the various parts of the URL.This is just rough parsing, I\'m not bothered about special cases. I guess there is some fau
What is the practical use of the formats \"%*\" in scanf(). If this format exists, there has to be some purpose behind it. The following program gives weird output.
This doesn\'t work: list($value) = sscanf(\'foo.bar\',\'%s.bar\'); echo $value; //foo.bar While this does:
Why do you require ampersand (&) in the scanf function. What will the output or type of error (compile or runtime) be in the following C code?
I have this sample code for converting 32 bit integers to ip addresses. #include <stdio.h> int main()
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