>>> float(str(0.65000000000000002)) 0.6开发者_如何学运维5000000000000002 >>> float(str(0.47000000000000003))
I have a UTF-8 formatted data file that contains thousands of floating point numbers.At the time it was designed the developers decided to omit the \'e\' in the exponential notation to save space.Ther
I did some speed testing to figure out what is the fastest, when doing multiplication or division on numbers. I had to really work hard to defeat the optimiser. I got nonsensical results such as a mas
I was looking at the implementation of compare(double, double) in the Java standard library (6). It reads:
I need a method in c# that makes me a string that look like a datetime out of a double/fl开发者_StackOverflow社区oat.
I want to get 1/7 with better precision, but it got truncated. How can I get better precision when I convert a rational number?
When calculating a golf handicap differential you are supposed to truncate the answer to 1 decimal place without rounding.No idea why but...
Yesterday I asked a floating point question, and I have another one. I a开发者_如何学Pythonm doing some computations where I use the results of the math.h (C language) sine, cosine and tangent functio
I tried this: float a = 1.4123; a = a & (1 << 3); I get a compiler error saying that the operand of & cannot be of type float.
I have an immutable Vector3 structure, and I\'m wondering how to best implement the .Equals() method so that it\'s useful and still satisfies the Guidelines for Overloading Equals().
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