and first of all, thank you for taking the time to read my question. I am trying to write a script, and I\'ve come across an issue which I am finding hard to solve. I am working with a pair of number
I am looking for an efficient (optionally standard, elegant and easy to implement) solution to multiply relatively large numbers, and store the result into one or several integers :
What doesn\'t this work: (int)08 == (int)09==0 But this and开发者_JS百科 this does? (int)07==7 (int)06==6
I have created a custom data type enum like so: create type \"bnfunctionstype\" as enum ( \'normal\',
I\'m wondering if anyone familiar with AMFPHP or low level data storage could explain why integers are being stored as two bytes instead of four.As far as I can tell, the AMF3 protocol demands a four
After debugging for a while I found what the error was, but I don\'t know how to fix it. I have an urlConf whit the name \'ver_caja\' who receives as argument the id of a caja object, and then call
i have a simply warning in my iphone dev code. NSUInteger *startIndex = 20; This code work, but i have a warning :
I am working in Windows MFC application..In my de开发者_开发问答sign am displaying the file details (type,name,size) in a CListCtrl control. I found those file details using FileStatus but when I try
I\'m just curious as to whether there is something built in开发者_如何学编程to either the C# language or the .NET Framework that tests to see if something is an integer
We\'ve started compiling both 32- and 64-bit versions of some of our applications.One of the guys on my project is encouraging us to switch all of our 32-bit integers to their 64-bit equivalents, even