In assembler: .globl _test _test: pushl %ebp movl %esp, %ebp movl 8(%ebp), %eax pushl %eax call printf popl %ebp
org 0x100 SEGMENT .CODE mov ah,0x9 mov dx, Msg1 int 0x21 ;string input mov ah,0xA mov dx,buff int 0x21 mov ax,0
So in assembly I declare the following String: Sample db \"This is a sample string\",0 In GDB I type \"p Sample\" (without quotes) and it spits out 0x73696854. I want the actual String to print out
How can I mult开发者_StackOverflow中文版iply and divide using only bit shifting and adding? To multiply in terms of adding and shifting you want to decompose one of the numbers by powers of two, like
I am trying to translate the following: Action: pushl %ebp movl %esp, %eax subl $0x32, %esp movl $0x0, -0x8(%eax)
I have a C array that contains binary x86_64 machine code, which I need to convert to assembly code on a Linux machine. I have no problem in converting the C array to a binary executable, 开发者_Stack
why does such a instruction as mul$t1, $v0 , 4 evaluates as expected. But mul$t1, 4 , $v0 results in a syntax error!
Is there any converter to convert a C function into ARM (v6) ASM code or I need to do it manually ? I am trying to gain the performance of a C func开发者_运维知识库tion on Iphone.Supposing you\'re in
Question What is the (non-trivial) difference between the following two x86 instructions? 39 /rCMP r/m32,r32Compare r32 with r/m32
I\'m converting some assembly code to C to be able to use it with the current compiler environment I have to work with.
加载中,请稍侯......