For instance, let\'s say I want to extract the price at 09:04:00 everyday from a timeseries that is formatted as:
I have the following data.frame d from an experiment: - Variable y (response, continuous) - Factor f (500 levels)
I have some data in python that is unixtime, value: [(1301672429, 274), (1301672430, 302), (1301672431, 288)...]
Say I have data concerning the position of animals on a 2d plane (as determined by video monitoring from a camera directly overhead). For example a matrix with 15 rows (1 for each animal) and 2 column
The diff command returns the differences between dates in a vector of dates in the R date format. I\'d like to control the units that are returned, but it seems like they are automatically determined,
Even though I found Hadley\'s post in the google group on POSIXct and geom_vline, I could not get it done. I have a time series from and would like to draw a vertical line for years 1998, 2005 and 201
The following开发者_如何学Python works fine in R myarray <- as.array(list(c(5,5), 9, c(4,2,2,4,6)))
The output of a time-series looks like a 开发者_开发知识库data frame: ts(rnorm(12*5, 17, 8), start=c(1981,1), frequency = 12)
10/03/2011 11/03/2011 12/03/2011 13/03/2011 14/03/201115/03/2011QUERYRESULT aaaaa14/03/2011 开发者_运维技巧bbb13/03/2011
I am working on a time series problem and want to decompose to get some basic info on lag. Goal is to evaluate lag of the output variable based on changes in the change variable as part of the example
加载中,请稍侯......