Input datas2 = [[(\"01/01/2011\", 1), (\"02/02/2011\", \"No\"), (\"03/03/2011\", 11)], [(\"01/01/2011\", 2), (\"03/03/2011\", 22), (\"22/22/2222\", \"no\")],
I\'m playing around with Haskell at the moment and thus stumbled upon the list comprehension feature.
I want to filter a list of tuples like [(1,22,1),(5,1,8),(8,3,4),(7,5,6)] using a list like [1,7] which would eventually give me the result [(1,22,1),(5,1,8),(7开发者_如何转开发,5,6)]; since (8,3,4) d
I am new to hask开发者_如何学Goell . I was wondering If I can do the following thing using just map and concat ?
What is the fastest way to get the last element of a list in Haskell. Also in next iterati开发者_JAVA百科on, I want to remove first and last element of the list. What is the most elegant way to do it?
This question already has answers here: Creating functions (or lambdas) in a loop (or comprehension) (6 answers)
In the Python Tutorial, it says: Why?I don\'t see how comprehensions are \"more flexible\".It seems to me to be only a differen开发者_如何学Pythonce in syntax.I can easily do:
Suppose that I have a list of cars : public class Car { private String brand; private String name; private String color;
I\'m starting to get used to list comprehension in Python but I\'m afraid I\'m using it somewhat improperly.I\'ve run into a scenario a few times where I\'m using list comprehension but immediately ta
I want to make an entries :: Map(String -> Entry) so I can easily access each entry by name.To this end, I have the code
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