#include <iostream> int main() { const int i=10; int *p =(int *) &i; *p = 5; cout<<&i<<\" \"<&开发者_StackOverflowlt;p<<\"\\n\";
Is the compiler allowed to eliminate the copy that is required for the by-value capture? vector<Image> movie1;
Let\'s say I 开发者_JAVA技巧have a C++0x tuple: tuple<int,int,int> t(1,2,3); Now I can do the following to extract the elements of t:
This question already has answers here: Closed 11 years ago. Possible Duplicate: Deprecation of the static keyword… no more ?
A couple of years ago I was taught, that in real-time applications such as Embedded Systems or (Non-Linux-)Ke开发者_开发百科rnel-developmentC++-Exceptions are undesirable. (Maybe that lesson was from
Is there a drawback to using the latter? Is std::make_pair more v开发者_StackOverflow中文版ersatile/compatible or are they truly interchangeable?
I have recently upgraded my g++ so I can enjoy lambda functions. Everything is great and I am very thankful to those who made it possible in C++ and gcc in particular. There is only one thing that I c
I\'m writing a function as part of an experiment with Boost.Interprocess. In the function I assign a string literal to a variable declared constexpr char*. When I do this, I get:
With std::is_base_of<A,B>::value one can check if a class A is a base class of class B. Is it also possible to query the compiler for all base classes of a class
I\'ve written a path class in my program for handling heirarchical path structures.I decided to use std::shared_ptr as the standard return type for the whole class since I\'m getting rather fond it.