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Why does the following... c=0; for i in $\'1\\n2\\n3\\n4\'; do echo iteration $c :$i:; c=$[c+1]; done print out...
I want to write a simple bash script that will act as a wrapper for an executable. How do I pass all开发者_C百科 the parameters that script receives to the executable? I tried
I have a list of timestamps in a text file. I want to figure out the times at which the change is more than a given threshold.
Question Rewritten: HOMEDIR=\"ftpuser\" REMOTEIP=\"1.1.1.1\" MYSQLPASS=\"password\" Q1=\"DROP USER \"$HOMEDIR\"_shop;\"
I\'ve seen here that what sets a programming language apart from a scripting language is the scripting engine. But I don\'t understand how it works, so I don\'t know the differe开发者_运维知识库nce.
I have a small ruby script in which I\'d like to use ActiveRecord to easily access a database mod开发者_如何学JAVAel. What is the best way to do it?require \'active_record\'
The Background I run an ASP.NET site using Graffiti CMS for a local charitable/service organization. The leaders of the organization want to start integrating a third-party back-end management syste
I am thinking of u开发者_运维百科sing sed for reading .properties file, but was wondering if there is a smarter way to do that from bash script?This would probably be the easiest way: grep + cut
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