I\'m writing a piece of software that will process huge amounts of data. For memory efficiency, some of the fields in the records being processed are stored in a single bitmap.
I am confused on the Bit Shift Operator开发者_运维知识库s (in c#). Can you shed light on why the value of \"a\" below returns \"1\" instead of \"4294967296\":
I have some C code, where an unsigned integer is shifted by a (signed) variable. For example, 1u << i;开发者_StackOverflow中文版
I understood how this solution works. int add_no_arithm(int a, int b) { if (b == 0) return a; int sum = a ^ b; // add without carrying
C++: How do I cast an int to an unsigned long and not change any bits? I want to pack and unpack values into memory. The word size is 64 bits.
I know that a LPARAM variable has certain bits set(inside it) that identify information such as long key presses & etc. when I receive a WM_KEYDOWN event.
I apologize for the Title of this Question, but I couldn\'t think of a better way to describe what I\'m trying to accomplish..
I am a student trying to implement the DES algorithm. I have a choice of 2 languages: C & Java. I did understand the algorithm, but am stuck at the very beginning as to manipulation of the key.
This question already has answers here: How do I set, clear, and toggle a single bit? (27 answe开发者_JAVA百科rs)
For example, if the pattern is as follows: bit[10010][1011][1000] position5432143214321 result214 I want to get the result from right to left po开发者_运维知识库sition as [2] [1] [4]If I understand
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