This isn\'t a question for a real-life project; I\'m only curious. We can increase an int using the increment operator (i++). You can define this operation as:
Using only adding, subtracting, and bitshifting, how can I multiply an integer by a given number? For example, I want to multiply an integer by 17.
I am working though a C++ book trying to learn some things.I am stuck on one thing, the bitwise not.I understand it flips all the bits but it is not working how I expect in C++.Here is the relevent co
I want to get the designated byte from a 32 bit integer. I am getting wrong values but I don\'t know why.
In C or C++, it\'s apparently possible to restrict the number of bits a variable has, so for example:
I was reading one question on the blog and the solution of t开发者_如何学JAVAhe question was to check whether 1 to n bits in \'k\' are set or not.
Just a quick and specific question, this has stumped me for half an hour almost. char * bytes = {0x01, 0xD8};
I\'m a little confused by the ~ operator. Code goes below: a = 1 ~a#-2 b = 15 ~b开发者_如何学运维#-16
I can only use these symbols: ! ~ & ^ | + << >> Here is the table I need to achieve: input | output开发者_JS百科
Is this possible? I have a signed int and need to shift it right 4 places. I cannot cast the int to an unsigned int, shift and then cast back. I need to deal with it after.
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