Find the maximum of two numbers. You should not use if-else or any other comparison operator. I found this question on online bulletin board, so i thought i should ask in StackOverflow
I have the following method that gets a rgb value and classifies it using a smaller palette: private static int roundToNearestColor( int rgb, int nrColors )
unsigned GetLowestBitPos(unsigned value) { double d = value ^ (value - !!value); return (((int*)&d)[1]>>20)-1023; // This is what I really need help understanding.
I\'m performing comparisons of objects based on the binary presence or absence of a set of features. These features can be represented by a bit string, such as this:
Im creating a class method and want to have a default argument value that contains constants: <?php
Assume that we have an array of integers (3x3) depicted as follows: +-+-+-+ 1| | +-+-+-+ |0|x|1| +-+-+-+
I\'m working on a project in computational biology and I need to store an index of locuses that differ between ma开发者_运维百科ny sequences. For now, I\'m using a B+Tree for that purpose, but I gues
~ & ^ | + << >> are the only operations I can use Before I continue, this is a homework question, I\'ve been stu开发者_开发技巧ck on this for a really long time.
Given an unsigned number, what is a good (preferably fast) way of getting the number of leading 1-bits?
I am trying to parse binary data that I receive in a string. I am not very familiar with bitwise operation.
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