Is it possible to have non-type template parameter which is actually a pointer to a class member? What I\'m looking to do is something like the following:
I have some classes that inherit from each other but they do so using templates. What I want is to effectively get a pointer and/or reference to one of the base classes as if it is one of the other po
I\'m trying to access session keys within a lo开发者_如何学运维op that needs to be dynamic, I think you\'ll get what I\'m going for by looking at my code that isn\'t working.
When you n开发者_StackOverflowavigate to File>New Project it gives you the templates for iOS and Mac OS X. I want to add my own platform that has templates. So it would show iOS, Mac OS X, and MY_PLAT
how can I force compiler, to generate whole class template? not just methods I use? I am sure I read it in template complete guide book, but I can not find it. It was one-line statement.
I\'ve been looking through the N3291 working draft of C++0x. And I was curious about extern template. Section 14.7.3 states:
Being new to php I really want to know how this is accomplished. You have a header and footer which are always present on the page and the content is the only thing different. So if you want to change
This question already has an answer here: C++ template typedef (1 answer) Closed 8 years ago. How should I typedef a template class ? Something like:
I need to check and see if a given type has a member variable. However when a type that is not a class or a struct is given, I get a compiler error.
I have a little conception problem. I created a View class that you use that way : $view = new View(\'title\');
加载中,请稍侯......