I was struggling with the issue described in this question (declaring a template function as a friend of a template class), and I believe the 2nd answer is what I want to do (forward declare the templ
Lets say you have simple templa开发者_Go百科te function (not class member for the sake of simplicity) with type specific specialization in the same .h file...
Consider the following piece of code: class B { private: // some data members public: friend bool operator==(const B&,const B&);
template<typename AT> class growVector { int size; AT **arr; AT* defaultVal; public: growVector(int size , AT* defaultVal);//Expects number of elements (5) and default value (NULL)
I am trying to do something like this: template <typename T,bool Strong=true> class Pointer {...};
I want to be able to define template <class TX> void f(const TX &x){ ... } template <class TY>
I\'m trying to implement this code to have different files to load for german, spanish or english开发者_如何转开发 browser languages of choice.
someone already asked this question, but the thread ended up with the original question not getting answered.
I have a templated class with a method for which I need a different implementation for a specific templat开发者_运维知识库e type. How do i get it done?You\'ll have to create a partial (or full) specia
Bumped into another templates problem: The problem: I want to partially specialize a container-class (foo) for the case that the objects are pointers, and i want to specialize only the delete-method.
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