I am having issues taking out duplicate entries from this query containing multiple LEFT OUTER JOINs SELECT s.Category,
I am trying to do Sqlite3 query via webpy framework.The query works in SQLiteManager. But with web.db i get \"sqlite3.OperationalError no such column a.id\".
Seemingly simple MySQL question, but I\'ve never had to do this before.. I have two tables, items and prices, with a one-to-many relationship.
The following two queries do not return the same result. Why ? Note : I found this question as a Mysql puzzle, I don\'t have more data on this question?
Assume that I have 2 tables : table1 :(20.000 records) idcode1code2somethingstatus table2: (7.500 records)
Can anyone tell me how can I write the equi开发者_运维技巧valent of a left join without really using left joins.
I have that one-to-many relationship going here.Plus, not all \"primary\" records will have a joined record in the second database table.
I seen topics explaining this but in my case it does not work. I have query ( SELECT * FROM my_table left join table2 on table2.id = my_table.id
This one is fairly specific, so I\'m hoping for a quick fix. I have a single result in my leaderboard table for each team. In my teams table, I have several results for each team (one result per game
My SELECT statement is essentially: SELECT *, user.user, response.survey FROM survey, user, response ORDER BY survey.added
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