I am looking to add a new item in a right click context menu for a certain file type. I suppose it would be easiest to run a batch file with the full path of the file as an argument. I need to rename
If I run the below program with the zip file which has some files with diacritic characters (e.g 1-2GF-969##JÖN.pdf) , I get IllegalArgumentException.
I get this error when I try to set a password to a zip file. Below is the code/error I get. Please give me an example of the correct wa开发者_JS百科y to do it.
i have a .zip file sitting on an IIS 6 webserver. i have an html file with a link to that zip file like this:
I am trying to use EC2 to zip up some files that are stored in an S3 bucket. I have gotten as far as successfully getting SWFUpload to work with PHP and upload the files to S3. I read that the best wa
I am currently doing this: <jar update=\"yes\" jarfile=\"${pwd}/dist/${release}_installer.jar\"> <zipfileset src=\"${pwd}/dist/app.jar\" includes=\"com/izforge/izpack/panels/**\"/>
I ha开发者_如何学Pythonve a zip file X and I\'d like do extract a single file, located in x/x/x/file.txt. How do I do this using Archive::Zip and Perl?You can use the extractMember method:
What I actually wanted to do is read zip file and then if it does contain folder then refuse it with some message.
I\'m trying ZIP a bundle of File\'s and return ZIP through a servlet. This works fine if I just have one file but when I try to add more it seems they are just being appended to the first ZipEntry and
I have a folder full of zipped files (about 200). I would like to transform this into a folder consisting only of unzipped files. What would be the easiest and quickest way to do this?
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