I have a little irritating problem. How can I count files in directory in Zip? I want to avoid use ZipFile.entries()开发者_开发知识库 and then test every enum.To count all files use ZipFile.size().
Is there any archive format that offers the following: be digitally sign-able with a digital certificate from a trusted source like Verisign - for preventing changes to the file (I am not referring
I have zip archive that contains a bunch of plain text files in it.I want to parse each text files data.Here\'s what I\'ve written so far:
I\'m new to Python and I am loving it, but was wondering if there was a better way to do a couple list manipulations.
In my app engine script (using the Python API), I\'m using this code to dynamically generate zip files and serve them back to the user. When I download and extract the generated zip file and I\'m runn
I want to make an Inno Setup script that installs an .exe file, several .dll files, a zip folder, and a reg开发者_如何学Cular folder.
Or am I thinking about this wrong?Basically, I want to be able to upload a zip file to a model, and after uploading I want to run a bunch of processes on it.It would be nice to be able to do this from
So far for Mime Types for Zip files I\'ve seen: application/octet-stream multipart/x-zip application/zip
I have a directory which contains a set of zipped files. each of these files has foo.txt file in it. How can I read this text file from each zip?
Right now I am using Oracle utility procedure, UTL_COMPRESS.LZ_COMPRESS(), to compress some data. But the problem is it compresses the thing using GZIP compatible format, which is not als开发者_如何学
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