In linux using gcc when开发者_如何学运维 I write a loop like this while(1 || 0) It enters the loop but when I write the loop like this
I used GCC and need to define big array of text, like const char* myArray[1000] = {\"red\", \"blue\", \"green\", \"yellow\", ...};
I am trying to create a linked list in my program and I am not able开发者_开发知识库 to allocate memory to the structure pointer using malloc(). How do I allocate memory to variables in GCC? The sampl
The short version: I try to compile MAGMA and get complains about missing symbols: testing_cgemm.o:testing_cgemm.cpp:(.text+0x2e7): undefined reference to `cudaMalloc\'
Is it hard coded into gcc\'s source or fetched somehow progra开发者_如何转开发matically?I think it is hardcoded in arch-specific folder, e.g. for sparc
I started out developing on C.I know what gcc is, libgcc, and so on . I\'ve done Windows/.NETdevelopment for years, and now I am playing with an iphone.
My code is in test.c: int main(){ return 0; } The dynamically shared libraries the executable compiled from it depends on are:
I\'m working on some code that uses Open Dynamics Engine.I\'ve worked with this code before on windows, but now I\'m moving over to unix so I can get experience working with C under a unix environment
i am using g++ (GCC) 4.6.0 and i am having trouble to producing the correct result. given the following simple for loop in c++
Now that I\'ve successfully installed Cython on Windows 7, I try to compile some Cython code using Cython, but gcc makes my life hard.
加载中,请稍侯......