From this article. Here\'s the code: float InvSqrt(float x){ // line 0 float xhalf = 0.5f * x; int i = *(int*)&x; // store floating-point bits in integer
目录1.基本介绍2.通道拆分2.1通过索引拆分2.2通过函数拆分3.通道合并总结1.基本介绍
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