I have another question related to the safe bool idiom: typedef void (Testable::*bool_type)() const;// const necessary?
This answer of @R. Martinho Fernandes shows, that the safe-bool idiom is apperently deprecated in C++11, as it can开发者_如何学Python be replaced by a simple
Hey guys, I have derived my class from the C++ safe bool idiom class from this p开发者_运维知识库age : The Safe Bool Idiom by Bjorn Karlsson
Could someone explain me why this code: class safe_bool_base { //13 protected: typedef void (safe_bool_base::*bool_type)() const;
Given the code below, how would you create/implement SR.h so that it produces the correct output WITHOUT any asterisks in your solution?
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