I heard that the 8086 has 16-bit registers which allow it to only address 64K of memory. Yet it is still able to address 1MB of memory which would require 20-bit registers. It does this by using anoth
Can someone please explain the functions of these three instructions? ORG 1000H MOV AX,CS MOV DS,AX I know what the code, data, and extra segments are in theory, but:
There\'s some \"supervisor\" bit to not let the \"user space\" do something li开发者_Python百科ke:
If a 32bit Operating System operated with a segmented memory model would their still be a 4GB limit? I was reading the Intel Pentium Processor Family Developer\'s Manual and it states that with a Seg
0040103ACAL开发者_StackOverflow社区L DWORD PTR DS:[40207A]USER32.MessageBoxA What does DS: mean?The instruction is loading a new EIP value from memory at ds:[40207A]. i.e. there\'s a function pointe
How c开发者_Python百科an I prepend a SS: or ES: using AT&T Assembly Syntax without adding in a .byte 0x36 or .byte 0x26?
From what I know, back in the days of 16bit PC\'s we had the Segment registers contain the address of each type of segment and you could access an offset with somethinglike this SS:[EDI], this would t
physical address=16*selector+offset but i don\'t know why multiplying 16开发者_Python百科 by selector?In order to be \"programmer-compatible\" with the Z80, yet still be able to use more than 64 kiB o
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