用Python实现石头剪刀布游戏
从控制台输入要出的拳 —— 剪刀(0)/石头(1)/布(2)
电脑 **随机** 出拳
比较胜负
增加错误输入的检测模块
# -*- coding = utf-8 -*- # @Time : 22:03 # @Author : huanh编程客栈uan # @File : test.py # @Software : PyCharm import random def show(num): if num == 0: sign = "剪刀" elif num == 1: sign = "石头" else: sign = "布" return sign while True: try: com = random.randint(0, 2) phttp://www.cppcns.comeople = int(input("请输入(剪刀:0,石头:1,布:2):")) if people > 3 or people < 0: print("请输入正确的数字") else: print("玩家出%s,电脑出%s" % (show(people), show(com))) if (people == 0 and com == 2) \ or (people == 1 and com == 编程客栈0) \ or (people == 2 and com == 1): print("玩家胜利") elif people == com: print("双方平局") elif people == 3: print("结束游戏") break else: 编程客栈 print("电脑胜利") except编程客栈 ValueError: print("请输入数字而不是字母")
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