开发者

Java8中Stream流求最大值最小值的实现示例

目录
  • 一、BigDecimal 求最大值和最小值
  • 二、Integer 求最大值和最小值
  • 三、Long 求最大值和最小值
  • 四、Double 求最大值和最小值

一、BigDecimal 求最大值和最小值

1. stream().reduce()实现

List<BigDecimal> list = new ArrayList<>(Arrays.asList(new BigDecimal("1"), new BigDecimal("2")));
BigDecimal max = list.stream().reduce(list.get(0), BigDecimal::max);
BigDecimal min = list.stream().reduce(list.get(0), BigDecimal::min);

2. stream().max()或stream().min()实现

List<BigDecimal> list = new ArrayList<>(Arrays.asList(new BigDecimal("1"), new BigDecimal("2")));
BigDecimal max = list.stream().max(Comparator.comparing(x ->开发者_Go教程; x)).orElse(null);
BigDecimal min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);

二、Integer 求最大值和最小值

1. stream().reduce()实python

List<Integer> list = new ArrayList<>(Arrays.asList(1, 2));
Integer max = list.stream().reduce(list.get(0), Integer::max);
Integer min = list.stream().reduce(list.get(0), Integer::min);

2. Collectors.summarizingInt()实现

List<Integer> list = new ArrayList<>(Arrays.asList(1, 2));
IntSummaryStatistics intSummaryStatistics = list.stream().collect(Collectors.summarizingInt(x -> x));
Integer max = intSummaryStatistics.getMax();
Integer min = intSummaryStatistics.getMin();

3. stream().max()或stream().min()实现

List<Integer> list = new ArrayList<>(Arrays.asList(1, 2));
Integhttp://www.devze.comer max = list.stream().max(Comparator.comparing(x -> x)).orElse(null);
Integer min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);

三、Long 求最大值和最小值

1. stream().reduce()实现

List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L));
Long max = list.stream().reduce(list.get(0), Long::max);
Long min = list.stream().reduce(list.get(0), Lo编程客栈ng::min);

2. Collectors.summarizingLong()实现

List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L));
LongSummaryStatistics summaryStatistics = list.stream().collect(Collectors.summarizingLong(x -> x));
Long max = summaryStatistics.gehttp://www.devze.comtMax();
Long min = summaryStatistics.getMin();

3. stream().max()或stream().min()实现

List<Long> list = new ArrayList<>(Arrays.asList(1L, 2L));
Long max = list.stream().max(Comparator.comparing(x -> x)).orElse(null);
Long min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);

四、Double 求最编程客栈大值和最小值

1. stream().reduce()实现

List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d));
Double max = list.stream().reduce(list.get(0), Double::max);
Double min = list.stream().reduce(list.get(0), Double::min);

2. Collectors.summarizingLong()实现

List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d));
DoubleSummaryStatistics summaryStatistics = list.stream().collect(Collectors.summarizingDouble(x -> x));
Double max = summaryStatistics.getMax();
Double min = summaryStatistics.getMin();

3. stream().max()或stream().min()实现

List<Double> list = new ArrayList<>(Arrays.asList(1d, 2d));
Double max = list.stream().max(Comparator.comparing(x -> x)).orElse(null);
Double min = list.stream().min(Comparator.comparing(x -> x)).orElse(null);

到此这篇关于Java8中Stream流求最大值最小值的实现示例的文章就介绍到这了,更多相关Java8 Stream流求最大值最小值内容请搜索我们以前的文章或继续浏览下面的相关文章希望大家以后多多支持我们!

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新开发

开发排行榜