postgresql 计算两点距离的2种方法小结

postgresql计算两点距离

下面两种方法：

select 
ST_Distance(
 ST_SetSRID(ST_MakePoint(115.97166453999147,28.716493914230423),4326)::geography,
 ST_SetSRID(ST_MakePoint(106.00231199774656,29.719258550486572),4326)::geography
),
ST_Length(
 ST_MakeLine(
 ST_MakePoint(115.97166453999147,28.716493914230423),
 ST_MakePoint(106.00231199774656,29.719258550486572)
 )::geography
)

备注：

ST_GeomFromText('LINESTRING(115.97166453999147 28.716493914230423,106.00231199774656 29.719258550486572)')与
ST_MakeLine(
	ST_MakePoint(115.97166453999147,28.716493914230423),
	ST_MakePoint(106.00231199774656,29.719258550486572)
)等价
 
ST_GeomFromText('POINT(115.97166453999147 28.716493914230423)',4326)与
ST_SetSRID(ST_MakePoint(115.97166453999147,28.716493914230423),4326)等价
 
ST_SetSRID(ST_MakePoint(115.97166453999147,28.716493914230423),4326)::geography与
Geography(ST_SetSRID(ST_MakePoint(115.97166453999147,28.716493914230423),4326))、
ST_GeographyFromText('SRID=4326;POINT(115.97166453999147 28.716493914230423)')等价
(::geography是postgis中的转换类型语法,把geometry转成geography)

补充：postgresql计算两点欧式距离（经纬度地理位置）

我就废话不多说了，大家还是直接看代码吧~

create or replace function getdistance
( 
 lon1 numeric,
 lat1 numeric, 
 lon2 numeric, 
 lat2 numeric 
) 
returns int 
as 
$body$ 
declare 
v_distance numeric;
v_earth_radius numeric;
radLat1 numeric;
radLat2 numeric;
v_radlatdiff numeric;
v_radlngdiff numeric;
begin 
 --地球半径
 v_earth_radius:=6378137;
  
 radLat1 := lat1 * pi()/180.0;
 radLat2 := lat2 * pi()/180.0;
 v_radlatdiff := radLat1 - radLat2;
 v_radlngdiff := lon1 * pi()/180.0 - lon2 * pi()/180.0; 
 v_distance := 2 * asin(sqrt(power(sin(v_radlatdiff / 2), 2) + cos(radLat1编程客栈) * coshttp://www.devze.com(radLat2) * power(sin(v_radlngdiff/2),2)));
 v_distance := round(v_distance * v_earth_radius);
 return vhttp://www.devze.com_distance; 
end;
$body$
language 'plpgsql' volatile;

create or replace function getdistance
( 
 i_lngbegin real,
 i_latbegin real, 
 i_lngend real, 
 i_latend real 
) 
returns float 
as 
$body$
/*
 * 
 * select getdistance_bygispoint(116.281524,39.957202,117.648673,38.42584) as distance;
 * */ 
declare 
v_distance real;
v_earth_radius real;
v_radlatbegin real;
v_radlatend real;
v_radlatdiff开发者_SQLite real;
v_radlngdiff real;
begin 
 --地球半径
 v_earth_radius:=6378.137;
  
 v_radlatbegin := i_latbegin * pi()/180.0;
 v_radlatend := i_latend * pi()/180.0;
 v_radlatdiff := v_radlatbegin - v_radlatend;
 v_radlngdiff := i_lngbe编程客栈gin * pi()/180.0 - i_lngend * pi()/180.0; 
 v_distance := 2 * asin(sqrt(power(sin(v_radlatdiff / 2), 2) + cos(v_radlatbegin) * cos(v_radlatend) * power(sin(v_radlngdiff/2),2)));
 v_distance := v_distance * v_earth_radius*1000; 
 return v_distance; 
end;
$body$ 
language 'plpgsql' volatile;

以上为个人经验，希望能给大家一个参考，也希望大家多多支持我们。如有错误或未考虑完全的地方，望不吝赐教。编程客栈