数据库中update与delete使用表别名的深入研究
目录
- 总结
- 1 Update
- 1.1 测试用例UPDATE users as a SET a.age = 111 WHERE a.name = 'Alice';
- 1.2 测试用例UPDATE users as a SET a.age = 111 WHERE name = 'Alice';
- 1.3 测试用例UPDATE users as a SET age = 111 WHERE a.name = 'Alice';
- 1.4 测试用例UPDATE users as a SET age = 111 WHERE name = 'Alice';
- 2 delete
- 2.1 测试用例delete users as a from a WHERE a.name = 'Alice';
- 2.2 测试用例delete users as a from a WHERE name = 'Alice';
- 总结
总结
Update
SQL语句示例 | oracle | SQLite | PostgreSQL | mysql & mariadb |
---|---|---|---|---|
UPDATE users as a SET a.age = 111 WHERE a.name = 'Alice'; | 报错 | 报错 | 报错 | 正常执行 |
UPDATE users as a SET a.age = 111 WHERE name = 'Alice'; | 报错 | 报错 | 报错 | 正常执行 |
UPDATE users as a SET age = 111 WHERE a.name = 'Alice'; | 报错 | 正常执行 | 正常执行 | 正常执行 |
UPDATE users as a SET age = 111 WHERE name = 'Alice'; | 报错 | 正常执行 | 正常执行 | 正常执行 |
Delete
SQL语句示例 | Oracle | SQLite | PostgreSQL | MYSQL & mariadb |
---|---|---|---|---|
delete from users as a WHERE a.name = 'Alice'; | 报错 | 报错 | 报错 | 报错 |
delete from users as a WHERE name = 'Alice'; | 报错 | 报错 | 报错 | 报错 |
1 Update
1.1 测试用例UPDATE users as a SET a.age = 111 WHERE a.name = 'Alice';
UPDATE users as a SET a.age = 111 WHERE a.name = 'Alice';
CREATE TABLE users ( name VARCHAR(255) NOT NULL, age INT ); INSERT INTO users (napythonme, age) VALUES ('Alice', 25); INSERT INTO users (name, age) VALUES ('Bob', 30); INSERT INTO users (name, age) VALUES ('Charlie', 35); INSERT INTO users (name, age) VALUES ('Alice', 40); SELECT * FROM users; UPDATE users as a SET a.age = 111 WHERE a.name = 'Alice'; SELECT * FROM users;
修改前表内容如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
1 ORACLE
执行报错
ORA-00971: missing SET keyword
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
2 sqlite
执行报错
Error: near line 12: near ".": syntax error
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
3 PG
执行报错
psql:commands.sql:12: ERROR: column "a" of relation "users" does not exist LINE 1: UPDATE users as a SET a.age = 111 WHERE a.name = 'Alice';
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
4 MYSQL & mariadb
执行正常
后表内容已经更新,如下:
name | age |
---|---|
Alice | 111 |
Bob | 30 |
Charlie | 35 |
Alice | 111 |
1.2 测试用例UPDATE users as a SET a.age = 111 WHERE name = 'Alice';
UPDATE users as a SET a.age = 111 WHERE name = 'Alice';
CREATE TABLE users ( name VARCHAR(255) NOT NULL, age jsINT ); INSERT INTO users (name, age) VALUES ('Alice', 25); INSERT INTO users (name, age) VALUES ('Bob', 30); INSERT INTO users (name, age) VALUES ('Charlie', 35); INSERT INTO users (name, age) VALUES ('Alice', 40); SELECT * FROM users; UPDATE users as a SET a.age = 111 WHERE name = 'Alice'; SELECT * FROM users;
修改前表内容如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
1 ORACLE
执行报错
ORA-00971: missing SET keyword
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
2 sqlite
执行报错
Error: near line 12: near ".": syntax error
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
3 PG
执行报错
psql:commands.sql:12: ERROR: column "a" of relation "users" does not exist LINE 1: UPDATE users as a SET a.age = 111 WHERE name = 'Alice';
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
4 MYSQL & mariadb
执行正常
后表内容已经更新,如下:
name | age |
---|---|
Alice | 111 |
Bob | 30 |
Charlie | 35 |
Alice | 111 |
1.3 测试用例UPDATBgzAFrbE users as a SET age = 111 WHERE a.name = 'Alice';
UPDATE users as a SET age = 111 WHERE a.name = 'Alice';
CREATE TABLE users ( name VARCHAR(255) NOT NULL, age INT ); INSERT INTO users (name, age) VALUES ('Alice', 25); INSERT INTO users (name, age) VALUES ('Bob', 30); INSERT INTO users (name, age) VALUES ('Charlie', 35); INSERT INTO users (name, age) VALUES ('Alice', 40); SELECT * FROM users; UPDATE users as a SET age = 111 WHERE a.name = 'Alice'; SELECT * FROM users;
修改前表内容如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
1 ORACLE
执行报错
ORA-00971: missing SET keyword
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
2 sqlite
执行正常
后表内容已经更新,如下:
name | age |
---|---|
Alice | 111 |
Bob | 30 |
Charlie | 35 |
Alice | 111 |
3 PG
执行正常
后表内容已经更新,如下:
name | age |
---|---|
Bob | 30 |
Charlie | 35 |
Alice | 111 |
Alice | 111 |
4 MYSQL & mariadb
执行正常
后表内容已经更新,如下:
name | age |
---|---|
Alice | 111 |
Bob | 30 |
Charlie | 35 |
Alice | 111 |
1.4 测试用例UPDATE users as a SET age = 111 WHERE name = 'Alice';
UPDATE users as a SET age = 111 WHERE name = 'Alice';
CREATE TABLE users ( name VARCHAR(255) NOT NULL, age INT ); INSERT INTO users (name, age) VALUES ('Alice', 25); INSERT INTO users (name, age) VALUES ('Bob', 30); INSERT INTO users (name, age) VALUES ('Charlie', 35); INSERT INTO users (name, age) VALUES ('Alice', 40); SELECT * FROM users; UPDATE users as a SET age = 111 WHERE name = 'Alice'; SELECT * FROM users;
修改前表内容如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
1 ORACLE
执行报错
ORA-00971: missing SET keyword
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
2 sqlite
执行正常
后表内容已经更新,如下:
name | age |
---|---|
Alice | 111 |
Bob | 30 |
Charlie | 35 |
Alice | 111 |
3 PG
执行正常
后表内容已经更新,如下:
name | age |
---|---|
Bob | 30 |
Charlie | 35 |
Alice | 111 |
Alice | 111 |
4 MYSQL & mariadb
执行正常
后表内容已经更新,如下:
name | age |
---|---|
Alice | 111 |
Bob | 30 |
Charlie | 35 |
Alice | 111 |
2 delete
2.1 测试用例delete users as a from a WHERE a.name = 'Alice';
delete users as a from a WHERE a.name = 'Alice';
CREATE TABLE users ( name VARCHAR(255) NOT NULL, age INT ); INSERT INTO users (name, age) VALUES ('Alice', 25); INSERT INTO users (name, age) VALUES ('Bob', 30); INSERT INTO users (name, age) VALUES ('Charlie', 35); INSERT INTO users (name, age) VALUES ('Alice', 40); SELECT * FROM users; delete users as a from a WHERE a.name = 'Alice'; SELECT * FROM users;
修改前表内容如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
1 ORACLE
执行报错
ORA-03048: SQL reserved word 'AS' is not syntactically valid following 'delete users '
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
2 sqlite
执行报错
Error: near line 12: near "users": syntax error
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
3 PG
执行报错
psql:commands.sql:12: ERROR: syntax error at or near "users" LINE 1: delete编程客栈 users as a from a WHERE a.name = 'Alice';
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
4 MYSQL & mariadb
执行报错
ERROR 1064 (42000) at line 12: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'as a from a WHERE a.name = 'Alice'' at line 1
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
2.2 测试用例delete users as a from a WHERE name = 'Alice';
delete users as a from a WHERE编程客栈 name = 'Alice';
CREATE TABLE users ( name VARCHAR(255) NOT NULL, age INT ); INSERT INTO users (name, age) VALUES ('Alice', 25); INSERT INTO users (name, age) VALUES ('Bob', 30); INSERT INTO users (name, age) VALUES ('Charlie', 35); INSERT INTO users (name, age) VALUES ('Alice', 40); SELECT * FROM users; delete users as a from a WHERE name = 'Alice'; SELECT * FROM users;
修改前表内容如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
1 ORACLE
执行报错
ORA-03048: SQL reserved word 'AS' is not syntactically valid following 'delete users '
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
2 sqlite
执行报错
Error: near line 12: near "users": syntax error
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
3 PG
执行报错
psql:commands.sql:12: ERROR: syntax error at or near "users" LINE 1: delete users as a from a WHERE name = 'Alice';
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
4 MYSQL & mariadb
执行报错
ERROR 1064 (42000) at line 12: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'as a from a WHERE name = 'Alice'' at line 1
之后查询表内容未发生变化,如下:
name | age |
---|---|
Alice | 25 |
Bob | 30 |
Charlie | 35 |
Alice | 40 |
总结
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