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What is the difference between print and puts?

For example in this line of code I wrote, print and puts produce different results.

1.upto(1000).e开发者_如何转开发ach { |i| print i if i % 2 == 0 }


puts adds a new line to the end of each argument if there is not one already.

print does not add a new line.


For example:

puts [[1,2,3], [4,5,nil]] Would return:

1
2
3
4
5

Whereas print [[1,2,3], [4,5,nil]] would return:

[[1,2,3], [4,5,nil]]
Notice how puts does not output the nil value whereas print does.


A big difference is if you are displaying arrays. Especially ones with NIL. For example:

print [nil, 1, 2]

gives

[nil, 1, 2]

but

puts [nil, 1, 2]

gives

1
2

Note, no appearing nil item (just a blank line) and each item on a different line.


print outputs each argument, followed by $,, to $stdout, followed by $\. It is equivalent to args.join($,) + $\

puts sets both $, and $\ to "\n" and then does the same thing as print. The key difference being that each argument is a new line with puts.

You can require 'english' to access those global variables with user-friendly names.


The API docs give some good hints:

print() → nil

print(obj, ...) → nil

Writes the given object(s) to ios. Returns nil.

The stream must be opened for writing. Each given object that isn't a string will be converted by calling its to_s method. When called without arguments, prints the contents of $_.

If the output field separator ($,) is not nil, it is inserted between objects. If the output record separator ($\) is not nil, it is appended to the output.

...

puts(obj, ...) → nil

Writes the given object(s) to ios. Writes a newline after any that do not already end with a newline sequence. Returns nil.

The stream must be opened for writing. If called with an array argument, writes each element on a new line. Each given object that isn't a string or array will be converted by calling its to_s method. If called without arguments, outputs a single newline.

Experimenting a little with the points given above, the differences seem to be:

  • Called with multiple arguments, print separates them by the 'output field separator' $, (which defaults to nothing) while puts separates them by newlines. puts also puts a newline after the final argument, while print does not.

    2.1.3 :001 > print 'hello', 'world'
    helloworld => nil 
    2.1.3 :002 > puts 'hello', 'world'
    hello
    world
     => nil
    2.1.3 :003 > $, = 'fanodd'
     => "fanodd" 
    2.1.3 :004 > print 'hello', 'world'
    hellofanoddworld => nil 
    2.1.3 :005 > puts 'hello', 'world'
    hello
    world
     => nil
  • puts automatically unpacks arrays, while print does not:

    2.1.3 :001 > print [1, [2, 3]], [4]
    [1, [2, 3]][4] => nil 
    2.1.3 :002 > puts [1, [2, 3]], [4]
    1
    2
    3
    4
     => nil
  • print with no arguments prints $_ (the last thing read by gets), while puts prints a newline:

    2.1.3 :001 > gets
    hello world
     => "hello world\n" 
    2.1.3 :002 > puts
    
     => nil 
    2.1.3 :003 > print
    hello world
     => nil
  • print writes the output record separator $\ after whatever it prints, while puts ignores this variable:

    mark@lunchbox:~$ irb
    2.1.3 :001 > $\ = 'MOOOOOOO!'
     => "MOOOOOOO!" 
    2.1.3 :002 > puts "Oink! Baa! Cluck! "
    Oink! Baa! Cluck! 
     => nil 
    2.1.3 :003 > print "Oink! Baa! Cluck! "
    Oink! Baa! Cluck! MOOOOOOO! => nil


puts call the to_s of each argument and adds a new line to each string, if it does not end with new line. print just output each argument by calling their to_s.

for example: puts "one two": one two

{new line}

puts "one two\n": one two

{new line} #puts will not add a new line to the result, since the string ends with a new line

print "one two": one two

print "one two\n": one two

{new line}

And there is another way to output: p

For each object, directly writes obj.inspect followed by a newline to the program’s standard output.

It is helpful to output debugging message. p "aa\n\t": aa\n\t


If you would like to output array within string using puts, you will get the same result as if you were using print:

puts "#{[0, 1, nil]}":
[0, 1, nil]

But if not withing a quoted string then yes. The only difference is between new line when we use puts.

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