How to detect mouseleave() on two elements at once?

Answer can be in vanilla js or jQuery. I w开发者_StackOverflowant to hide a div with the id "myDiv" if the user is no longer hovering over a link with the id "myLink" or a span with the id "mySpan". If the user has his mouse over either element "myDiv" will still show, but the second the user is not hover over either of the two (doesn't matter which element the user's mouse leaves first) "myDiv" will disappear from the face of existence.

In other words this is how I detect mouse leave on one element:

$('#someElement').mouseleave(function() {

   // do something

});

but how to say (in a way that will actually work):

$('#someElement').mouseleave() || $('#someOtherElement').mouseleave()) {

   // do something

});

How to detect this?

Something like this should work:

var count = 0;
$('#myLink, #mySpan').mouseenter(function(){
    count++;
    $('#myDiv').show();
}).mouseleave(function(){
    count--;
    if (!count) {
        $('#myDiv').hide();
    }
});

jsfiddle

You could use a multiple selector:

$("#someElement, #someOtherElement").mouseleave(function() {
   // Do something.
});

You can beautifully use setTimeout() to give the mouseleave() function some "tolerance", that means if you leave the divs but re-enter one of them within a given period of time, it does not trigger the hide() function.

Here is the code (added to lonesomeday's answer):

var count = 0;
var tolerance = 500;
$('#d1, #d2').mouseenter(function(){
    count++;
    $('#d3').show();
}).mouseleave(function(){
    count--;
    setTimeout(function () {
        if (!count) {
            $('#d3').hide();
        }
    }, tolerance);
});

http://jsfiddle.net/pFTfm/195/

I think, it's your solution!!!

$(document).ready(function() {
    var someOtherElement = "";
    $("#someElement").hover(function(){
        var someOtherElement = $(this).attr("href");
        $(someOtherElement).show();
    });
    $("#someElement").mouseleave(function(){
        var someOtherElement= $(this).attr("href");
        $(someOtherElement).mouseenter(function(){
        $(someOtherElement).show();
        });
        $(someOtherElement).mouseleave(function(){
        $(someOtherElement).hide();
        });

    });
});

----
html
----
<div id="someElement">
                <ul>
                  <li><a href="#tab1">element1</a></li>
                  <li><a href="#tab2">element2</a></li>
        </ul>       
</div>

<div id="tab1" style="display: none"> TAB1 </div>
<div id="tab2" style="display: none"> TAB1 </div>

While the answer from lonesomeday is perfectly valid I changed my html to have both elements in one container. I originally wanted to avoid this hence I had to do more refactoring for my clients in other html templates, but I think it will pay out on the long term.

<div id="my-container">
 <div class="elem1">Foo</div>
 <div class="elem2">Bar</div>
</div>

$('#my-container').mouseleave(function() { console.log("left"); });