line break on regular expressions

I'm trying to replace everything between 2 tags, but I'm not able to build the right expression.

This is what I did: /<tag>(.*|\n*)</tag>/

I want it to capture any characters including line breaks.

This is an example of what I need to capture:

 <tag>
       <div class="feed_title">Some Title</div>
       <div class="feed_content">Some text</div>
    </tag>

Can some of you tell me what I'm开发者_JS百科 doing wrong?

Here is a link to RegExr and a full example of what the content looks like: http://regexr.com?2t4n1

'#.#m'

The m means MULTILINE, it makes the point able to match the newlines=line breaks \n

EDIT:

as it has been corrected by sharp eyes and good brain, it is evidently '#.+#s'

EDIT2:

As Michael Goldshteyn said, this should work

$ch = '<tag>\s+<div class="feed_title">Some Title</div>\s+<div class="feed_content">Some text</div>\s+</tag>'

preg_match('#<tag>(.+?)</tag>#s',$ch,$match)

There is another solution, without s flag, I think:

preg_match('#<tag>((.|\s)+?)</tag>#',$ch,$match)

But it's more complicated

.

EDIT 3:

I think that the presence of \s in $ch is a nonsense. \s is used in a RE, not in strings.

I wrote that because I was thinking that it could be blanks or \t that could be before <tag> and at the beginning of other lines

\t is written with an escape; that's not a reason to write \s also in a string

Perhaps you meant to do this?

# The ... in this example is your text to match
preg_match("#<tag>(.*?)</tag>#s","...",$matches); 

Here is a link to an article on XML data extraction using regular expressions using PHP, which has some good examples.