开发者

How to close a window/activity after a certain amount of inactivity

I'm designing a music player app for Android that will feature pop-up controls. I'm currently trying to get these controls to close after a certain period of inactivity but there doesn't seem to be a clearly documented method of doing this. So far I have managed to cobble the following solution together using a few suggestions both from this site and others.

private Timer originalTimer = new Timer();

@Override
public void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    setContentView(R.layout.playcontrols);

    View exitButton = findViewById(R.id.controls_exit_pane);
    exitButton.setOnClickListener(this);
    View volUpButton = findViewById(R.id.controls_vol_up);
    volUpButton.setOnClickListener(this);
    View playButton = findViewById(R.id.controls_play);
    playButton.setOnClickListener(this);
    View volDownButton = findViewById(R.id.controls_vol_down);
    volDownButton.setOnClickListener(this);

    musicPlayback();

    originalTimer.schedule(closeWindow, 5*1000);    //Closes activity after 10 seconds of inactivity

}

And the code that should close the window

//Closes activity after 10 seconds of inactivity
public void onUserInteraction(){
    closeWindow.cancel();   //not sure if this is required?
    originalTimer.cancel();
    originalTimer.schedule(closeWindow, 5*1000);
}

private TimerTask closeWindow = new TimerTask() {

    @Override
    public void run() {
        finish();
    }
};

The above code makes perfect sense to me but it force closes upon any user interaction. It does however close normally if untouched and won't close after interaction if I remove the 开发者_如何学Csecond schedule, so this seems to be the problem. Also note that I imagine I will be moving this timing task to another thread to help keep the UI snappy. I need to get it working first though :D. If there's any more info I need to supply please ask and thanks for any help...Ye guys are brilliant!


Based on @CommonsWare's suggestion, switched to a Handler. Works perfectly. Thanks very much!

private final int delayTime = 3000;
private Handler myHandler = new Handler();

@Override
public void onCreate(Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    setContentView(R.layout.playcontrols);

    View exitButton = findViewById(R.id.controls_exit_pane);
    exitButton.setOnClickListener(this);
    View volUpButton = findViewById(R.id.controls_vol_up);
    volUpButton.setOnClickListener(this);
    View playButton = findViewById(R.id.controls_play);
    playButton.setOnClickListener(this);
    View volDownButton = findViewById(R.id.controls_vol_down);
    volDownButton.setOnClickListener(this);

    musicPlayback();

    myHandler.postDelayed(closeControls, delayTime);

}

and the other methods...

//Closes activity after 10 seconds of inactivity
public void onUserInteraction(){
    myHandler.removeCallbacks(closeControls);
    myHandler.postDelayed(closeControls, delayTime);
}

private Runnable closeControls = new Runnable() {
    public void run() {
        finish();
        overridePendingTransition(R.anim.fadein, R.anim.fadeout);
    }
};


To complete the answer above, note that the Activity.onUserInteraction() is adequate only if you care about clicks.

The documentation at http://developer.android.com/reference/android/app/Activity.html#onUserInteraction%28%29 states: "Note that this callback will be invoked for the touch down action that begins a touch gesture, but may not be invoked for the touch-moved and touch-up actions that follow."

Actual implementation proved it indeed ignores all movements on the tablet, which means the clock is never reset while, say, drawing without releasing the finger. On the other hand, it also means that the clock is not reset too often, which limits the overhead.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜