开发者

Returning ID with information MySQL/PHP

$sql  = 'SELECT `name`, `course`, `id` FROM `teacher`';
$rows = $mysql_conn->fetch_array($sql);
foreach($rows as $record) {
    $search_results[$record['name']] = $record['course'];
}

foreach($search_results as $teacher=>$string_courses){
    $array_courses = explode('-',$string_courses);
    $search_results[$teacher] = $array_courses;
}

foreach($search_results as $teacher=>$courses){
    foreach($courses as $period => $course){
        if($course == $id) {
            $name               = explode(',', $teacher);
            $results开发者_开发技巧[$period][] = '<a href="?page=teacher&id='.ID HERE.'">'.$name[0].'<br />'.$name[1].'</a>';
        }
    }
}

Where it says ID HERE, I want the ID returned for each teacher inserted there but I do not know how to insert it so that it passes through.


You're building your array in a weird way, using $record['name'] as a key, change that to $record['id'] and you have a better start.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜