Deleting rows from SQLite table when no match exists in another table
I need to delete rows from an SQLite table where their 开发者_如何学Gorow IDs do not exist in another table. The SELECT statement returns the correct rows:
SELECT * FROM cache LEFT JOIN main ON cache.id=main.id WHERE main.id IS NULL;
However, the delete statement generates an error from SQLIte:
DELETE FROM cache LEFT JOIN main ON cache.id=main.id WHERE main.id IS NULL;
The error is: SQLite Error 1 - near "left": syntax error. Is there another syntax I could use?
SQLite apparently doesn't support joins with the delete statement, as you can see on the Syntax diagrams. You should however be able to use a subquery to delete them.
ie.
DELETE FROM cache WHERE id IN
(SELECT cache.id FROM cache LEFT JOIN main ON cache.id=main.id WHERE main.id IS NULL);
(Not tested)
Since you going down the route of subquery, might as well get rid of the join altogether and simplify the query:
DELETE FROM cache WHERE id NOT IN (SELECT id from main);
Solution from @wimvds didn't work for me, so I modified the query and removed WHERE condition:
DELETE FROM FirstTable WHERE firstTableId NOT IN (SELECT SecondTable.firstTableId FROM SecondTable LEFT JOIN FirstTable ON FirstTable.firstTableId=SecondTable.firstTableId)
This deletes all the rows from FirstTable that do not have their id assigned to any row in SecondTable.
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