Java Webservice URL in JSF
I created a JSF application which also offers some Webservices. The webservices are created via annotations.
Now I want to create a webserviceInfo.xhtml Page , where I get all the needed webservice Information.
When I g开发者_StackOverflowo to the address http://our.server.com/application/OurWebserviceName, I get all the information needed to access the webservice (this info page is generated automatically by Glassfish ).
To include this page, I did the following in the webserviceInfo.xhtml:
<iframe scrolling="automatic" width="971" height="1000" src="#{myBean.generateUrlToWebservice()}/OurWebserviceName"/>
Where:
public String generateUrlToWebservice(){
FacesContext fc = FacesContext.getCurrentInstance();
String servername = fc.getExternalContext().getRequestServerName();
String port = String.valueOf(fc.getExternalContext().getRequestServerPort());
String appname = fc.getExternalContext().getRequestContextPath();
return "http://"+servername+":"+port+appname;
}
Is there a more elegant solution to this?
BR, Rene
Use a page-relative URL.
<iframe src="OurWebserviceName"></iframe>
Or make use of <base> tag with little help of JSTL functions taglib.
<html xmlns:fn="http://java.sun.com/jsp/jstl/functions">
...
<base href="#{fn:replace(request.requestURL, request.requestURI, '')}#{request.contextPath}"></base>
This way any URL which doesn't start with scheme or / is always relative to this URL.
Or if you really need to do it in JSF the following gives less headache with scheme and port.
HttpServletRequest request = (HttpServletRequest) externalContext.getRequest();
return request.getRequestURL().toString().replace(request.getRequestURI, "") + request.getContextPath();
Better will be if you gets all parameters dynamically like protocol (http,https..) and pages (after app name)
public String generateUrlToWebservice(){
FacesContext fc = FacesContext.getCurrentInstance();
ExternalContext exContext = fc.getExternalContext();
String servername = exContext.getRequestServerName();
String port = String.valueOf(exContext.getRequestServerPort());
String appname = exContext.getRequestContextPath();
String protocol = exContext.getRequestScheme();
String pagePath = exContext.getInitParameter("pagePath"); //read it from web.xml
return protocol +"://"+servername+":"+port+appname+pagePath;
}
加载中,请稍侯......
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