PHP: Any failure? How to make `echo $report` return right value trough `class validate`?
Why echo $report
has empty value? Any failure in class validate
?
How to make it return right value trough class validate
?
<?php
class validate{
function status($status){
header('Location:',true,$status);
$report="Error: $status";
}
function fine(){
$report='Ok!';
}
}
$validate=new validate($id);
//$id=0;
$id=(isset($id) ? $id : NULL);
(($id==0) ? $validate->fine() 开发者_如何学JAVA: $validate->status('404'));
echo $report; // Why it has empty value? How to solve it?
?>
Declare it as a public variable in the class, set it using $this->report, and echo it using $validate->report.
Example:
class validate{
public $report;
function status($status){
header('Location:',true,$status);
$this->report="Error: $status";
}
function fine(){
$this->report='Ok!';
}
}
$report is a class variable in your validate object. echo $report
is looking for a variable in the local scope, not your object. Try echo $validate->report
instead.
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