[Grails/Groovy]minimum value of Map entries
Query: how can i pul开发者_如何转开发l minimum value from a map in Grails
So far i have found following code to get minimum value from a map in groovy
["Java":1, "Groovy":4, "JavaScript":2].min{it.value}
but it donot work in Grails
i have tried following piece of code
def map = ["Java":1, "Groovy":4, "JavaScript":2]
println map.min{it.value}
assert map.min{it.value}==1
Thanks in advance
If you want the minimum value from the map, you can do:
def map = ["Java":1, "Groovy":4, "JavaScript":2]
println map.values().min()
assert map.values().min() == 1
edit
Also, the closure accepting version of map.min
has been in Groovy since 1.7.6, and Grails (as of v1.3.6) uses Groovy 1.7.5
min()
doesn't return a minimum value returned by argument closure, it returns the element of a collection for which the closure returns minimum.
map.min {it.value}
is valid call, but it's not a value. It's a MapEntry
, with key
and value
properties. So map.min{it.value}.value
would do.
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