.NET functions disassembled
When disassembling .NET functions, I notice that they all start with a similair pattern. What does this initial code do?
This code appear before the actual code for what the function is supposed to do. Is it some sort of parameter count verification?
fun开发者_如何学编程c1
private static void Foo(int i)
{
Console.WriteLine("hello");
}
00000000 push ebp
00000001 mov ebp,esp
00000003 push eax
00000004 mov dword ptr [ebp-4],ecx
00000007 cmp dword ptr ds:[005C14A4h],0
0000000e je 00000015
00000010 call 65E0367F
//the console writleline code follows here and is not part of the question
func2
static private void Bar()
{
for (int i = 0; i < 1000; i++)
{
Foo(i);
}
}
00000000 push ebp
00000001 mov ebp,esp
00000003 push eax
00000004 cmp dword ptr ds:[006914A4h],0
0000000b je 00000012
0000000d call 65CC36CF
// the for loop code follows here
func3
private static void Foo()
{
Console.WriteLine("hello");
}
00000000 push ebp
00000001 mov ebp,esp
00000003 cmp dword ptr ds:[005614A4h],0
0000000a je 00000011
0000000c call 65E3367F
[Edit] So is this a correct description of it?
//fix stackframe
00000000 push ebp
00000001 mov ebp,esp
//store eax so it can be used locally
00000003 push eax
//ensure static ctor have been called
00000004 cmp dword ptr ds:[006914A4h],0
//it has been called, ignore it
0000000b je 00000012
//it hasn't been called, call it now
0000000d call 65CC36CF
or?
This prologue has two parts.
Setting up the stackframe
This stores the current EBP register on the stack and then assigns the value of the stackpointer(ESP) to EBP.
push ebp
mov ebp,esp
If there are local variables that are stored on the stack (i.e. not enough space in the registers available) then ESP will be moved by their size to build the stackframe of the current function.
And at the end of the function you'll see these operations reversed, so the stack-frame of the previous function gets restored.
EBP should always point to the beginning of the stackframe of the current function
ESP to the end(which has a lower address on x86 because the stack grows downwards).
This is part of the common calling conventions and needed for stack unrolling when an exception is thrown. This is not .net specific and used by most calling conventions on windows/x86.
After setting up the stackframe its common to store some registers on the stack. That's because you might want to use certain registers as temporary variables, but the calling convention requires your function to conserve them. So you need to back them up on the stack. Which registers must be preserved and which can be modified depends on the calling convention you use.
When referring to local variables on the stack you can use [ebp-x]
where ebp
points to the beginning of the stackframe, and x is an offset which indicates where in the stackframe the variable is stored. Alternatively you can use [esp+y]
with an offset from the end of the stackframe.
Call to the static constructor/initializer
As danbystrom noticed the second part is most likely the call to a static constructor/initializer. Since the static constructor is not called on program startup but on the first access, every access for which the jitter can't guarantee that the static constructor has already executed needs to check if it has been called, and then calls it if not.
00000004 cmp dword ptr ds:[006914A4h],0
0000000b je 00000012
0000000d call 65CC36CF
This is something like if (globalVar!=0) Call Function_65CC36CF
. Where most likely the global var indicates if the static constructor has run, and the call is a call to the static constructor.
As far as I know your comments on the disassembly are correct.
Check this OldNewThing blog entry on stackframes: How to rescue a broken stack trace: Recovering the EBP chain
Since your methods are all static: the code is used to check if the class' static initializer has yet been executed.
00000007 cmp dword ptr ds:[005C14A4h],0 ; test if static initializer has executed
0000000e je 00000015 ; skip call to initializer if already done
00000010 call 65E0367F ; call static initializer
00000015 .... ; continue with the method's code
If you're talking about the push and the mov, it's just fixing up the callstack. I'm not sure what the remainder of those segments is doing off the top of my head.
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