Does array_a contain all elements of array_b
If this is $array_b
$array_b = array('red', 'green', 'blue');
What's an efficient way to compare it to $array_a
and get a boolean as to whether $array_a
contains all elements of the above $array_b
.
This is the output I'm trying to get to
//false, because it's missing the red from `$array_b`
$array_a = array('green', 'blue');
//true, because it contains all 3 from `$array_b`
$array_a = array('red', 'green', 'blue');
//t开发者_如何学JAVArue, because it contains all 3 from `$array_b`
//even though there's an extra orange and cyan
$array_a = array('red', 'green', 'blue', 'orange', 'cyan');
What's a good way to do this without nasty nested loops that are hard to keep track of?
if (count(array_intersect($array_a, $array_b)) == count($array_b)) {
...
}
or as function
function function_name($array_a, $array_b) {
return count(array_intersect($array_a, $array_b)) == count($array_b);
}
$boolean = count(array_diff($array_b, $array_a)) == 0 ? true : false;
empty()
is faster than count()
, and diff is faster than intersect.
$diff=array_diff($array_a, $array_b);
if(empty($diff))
{
...
}
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