How to print integers in assembly loop [duplicate]

This question already has answers here: Outputting integers in assembly on Linux (2 answers) Closed 7 years ago.

I'm expirimenting with assembly. Now I have a simple while loop starting with eax = 1 and then loop until eax = 10. In the loop i use a print macro to print te progress (should print 1 - 10) but it doesnt work..

section .bss
    buffer resd 1

section .text
    global _start


%macro write 3
    mov eax, 4
    mov ebx, %1
    mov ecx, %2
    mov edx, %3
    int 80H
%endmacro

_start:
    xor eax, eax
    inc eax

while:
    cmp eax, 10
    jg end

开发者_如何学JAVA    mov [buffer], eax

    write 1, [buffer], 1

    mov eax, [buffer]       

    inc eax
    jmp while

end:
    mov eax, 1
    xor ebx, ebx
    int 0x80

The c equivalent is:

#include <stdio.h>

int main(void)
{
    unsigned int i = 1;
    while(i <= 10)
    {
        printf("%d", i);
        i++;
    }

    return 0;
}

So my question is.. how can i use the write macro to print the values? What do i have to change in it?

Thanks

---

Ok, there are a couple of things:

1) The syscall you are calling writes an ascii string, so you have to convert from integer to ascii. From 0 to 9 you have to add 30h to the integer (if I remember well) to get the corresponding ascii code, but for larger number it gets more and more complicated.

2) The size you are passing to sys_write (1) is wrong, you should pass 3 (2 bytes to hold the number + one terminating null byte).

And since you have to change the value of all registers in order to call sys_write I would suggest you using esi or edi to hold the counter or push, then pop it when writing.