MySQL SELECT query string matching

Normally, when querying a database with SELECT, its common to want to find the records that match a given search string.

For example:

SELECT * FROM customers WHERE name LIKE '%Bob Smith%';

That query should give me all records where 'Bob Smith' appears anywhere i开发者_JAVA技巧n the name field.

What I'd like to do is the opposite.

Instead of finding all the records that have 'Bob Smith' in the name field, I want to find all the records where the name field is in 'Robert Bob Smith III, PhD.', a string argument to the query.

Just turn the LIKE around

SELECT * FROM customers
WHERE 'Robert Bob Smith III, PhD.' LIKE CONCAT('%',name,'%')

You can use regular expressions like this:

SELECT * FROM pet WHERE name REGEXP 'Bob|Smith'; 

Incorrect:

SELECT * FROM customers WHERE name LIKE '%Bob Smith%';

Instead:

select count(*)
from rearp.customers c
where c.name  LIKE '%Bob smith.8%';

select count will just query (totals)

C will link the db.table to the names row you need this to index

LIKE should be obvs

8 will call all references in DB 8 or less (not really needed but i like neatness)