Regex created via new RegExp(myString) not working (backslashes)
So, I'm trying to write a regex that matches all numbers. Here is that regex:
/\b[\d \.]+\b/g
And I try to use it on the string:
开发者_开发问答100 two 100
And everything works fine; it matches both of the numbers.
But I want to rewrite the regex in the form:
new RegExp(pattern,modifiers)
Because I think it looks clearer. So I write it like this:
new RegExp('\b[\d \.]+\b','g')
But now it won't match the former test string. I have tried everything, but I just can't get it to work. What am I doing wrong?
Your problem is that the backslash in a string has a special meaning; if you want a backslash in your regexp, you first need to get literal backslashes in the string passed to the regex:
new RegExp('\\b[\\d \\.]+\\b','g');
Note that this is a pretty bad (permissive) regex, as it will match ". . . "
as a 'number', or "1 1...3 42"
. Better might be:
/-?\d+(?:\.\d+)?\b/
Note that this matches odd things like 0000.3
also does not match:
- Leading
+
- Scientific notation, e.g.
1.3e7
- Missing leading digit, e.g.
.4
Also, note that using the RegExp constructor is (marginally) slower and certainly less idiomatic than using a RegExp literal. Using it is only a good idea when you need to constructor your RegExp from supplied strings. Most anyone with more than passing familiarity with JavaScript will find the /.../
notation fully clear.
精彩评论