Get first record per identifier group in SQL

Code     Description     Whatever
---------------------------------
1        stuff           blah
1        something       meh
2        yah             bong
2        never           hammer time

How do I get a results set from this with each Code only present once? (I don't overly care which record for that code it is).

So I want....

1        stuff           blah
2        yah            开发者_如何学C bong

SELECT *
FROM (
SELECT * , row_number() over(partition by code order by Description) as id
from yourTable
) temp
WHERE id = 1

I think this is sql server only

You first need to pick a column which determines what counts as 'the first result'. In my example I chose Description:

SELECT * FROM YourTable first 
WHERE 
   (SELECT COUNT(*) FROM YourTable previous 
    WHERE previous.Code=first.Code AND previous.Description < first.Description) = 0