In XSLT 1.0, how can I access attributes of a particular XML element when it is one of multiple elements with the same name?
I blame the Google Search Appliance for making me ask this question.
Here is a snippet of the XML returned by the Appliance:
<GSP VER="3.2">
<TM>0.073846</TM>
<Q>test</Q>
<PARAM name="entqr" value="0" original_value="0"/>
<PARAM name="access" value="p" original_value="p"/>
<PARAM name="output" value="xml_no_dtd" original_value="xml_no_dtd"/>
<PARAM name="sort" value="date:D:L:d1" original_value="date%3AD%3AL%3Ad1"/>
<PARAM name="ud" value="1" original_value="1"/>
<PARAM name="ie" value="UTF-8" original_value="UTF-8"/>
<PARAM name="btnG" value="Search" original_value="Search"/开发者_Python百科>
<PARAM name="client" value="default_frontend" original_value="default_frontend"/>
<PARAM name="oe" value="UTF-8" original_value="UTF-8"/>
<PARAM name="q" value="I like stuff" original_value="I like stuff"/>
...
I need to do an xsl:value-of for a specific one of those PARAM elements, conditionally based on its name. e.g. I need to output the @value for the PARAM element with @name="client".
Thanks!
You can declare xsl:key as a top-level element:
<xsl:key name="param" match="PARAM" use="@name"/>
and then use key(key-name,value) function.
<xsl:value-of select="key('param','q')/@value"/>
It takes time to 'init' key but further it's much faster than selecting node[predicate] each time. So it's better to use it when you need to access PARAMs multiple times.
http://www.w3.org/TR/xslt#key
Also, knowing your tree, you can match your nodes (PARAM) more accurately.
Try using predicates on your XPath statements! try something like:
<xsl:value-of select="PARAM[@name='output']/@value"/>
<xsl:value-of select="//PARAM[@name='client']/@value" />
You didn't add the complete XML document. In case there is a default namespace involved you will have to declare a prefix that you want to use and prepend that to the element and attribute names respectively.
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