How to display two table columns per row in php loop
I would like to display data, two columns per row during my foreach. I would like my result to look li开发者_Go百科ke the following:
<table>
<tr><td>VALUE1</td><td>VALUE2</td></tr>
<tr><td>VALUE3</td><td>VALUE4</td></tr>
<tr><td>VALUE5</td><td>VALUE6</td></tr>
</table>
Any help would be greatly appreciated.
You can use array_chunk()
to split an array of data into smaller arrays, in this case of length 2, for each row.
<table>
<?php foreach (array_chunk($values, 2) as $row) { ?>
<tr>
<?php foreach ($row as $value) { ?>
<td><?php echo htmlentities($value); ?></td>
<?php } ?>
</tr>
<?php } ?>
</table>
Note that if you have an odd number of values, this will leave a final row with only one cell. If you want to add an empty cell if necessary, you could check the length of $row
within the outer foreach
.
$i=0;
foreach ($x as $key=>$value)
{
if (fmod($i,2)) echo '<tr>';
echo '<td>',$value,'</td>';
if (fmod($i,2)) echo '</tr>';
$i++;
}
this will output TR (row) each second time
ps: i haven't tested the code, so maybe you will need to add ! sign before fmod, if it doesn't output TR on first iteration, but on second iteration in the beginning...
This would give you great table and for loop concept--
<table border="1" cellspacing="0" cellpadding="2">
<?php
for($x=1; $x<=20; $x++)
{
echo "<tr>";
for($y=1; $y<=20; $y++)
{
echo "<td>";
echo $x*$y;
echo "</td>";
}
echo "</tr>";
}
?>
</table>
<table>
<?php
$i=0;
foreach ($x as $key=>$value)
{
if (!$i%2) echo '<tr>';
echo '<td>',$value,'</td>';
if ($i%2) echo '</tr>';
$i++;
}
?>
</table>
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