Largest and smallest number in an array
This works perfectly...but when I use foreach
instead of for
this doesn't works. I can't understand for
and foreach
are same.
namespace ConsoleApplication2
{
class Program
{
static void Main(string[] args)
{
int[] array = new int[10];
Console.WriteLine("enter the array elements to b sorted");
for(int i=0;i<10;i++)
{
array[i] = Convert.ToInt32(Console.ReadLine());
}
int smallest = array[0];
for(int i=0;i<10;i++)
{
if(array[i]<smallest)
{
smallest=array[i];
}
}
int largest = array[9];
for(int i=0;i<10;i++)
{
if (array[i] > largest)
{
largest = array[i];
}
}
Console.WriteLine("the smallest no is {0}", smallest);
Console.WriteLine("the largest no is {0}", larges开发者_运维百科t);
Console.Read();
}
}
}
Why are you not using this?
int[] array = { 12, 56, 89, 65, 61, 36, 45, 23 };
int max = array.Max();
int min = array.Min();
If you need to use foreach (for some reason) and don't want to use bult-in functions, here is a code snippet:
int minint = array[0];
int maxint = array[0];
foreach (int value in array) {
if (value < minint) minint = value;
if (value > maxint) maxint = value;
}
static void PrintSmallestLargest(int[] arr)
{
if (arr.Length > 0)
{
int small = arr[0];
int large = arr[0];
for (int i = 0; i < arr.Length; i++)
{
if (large < arr[i])
{
int tmp = large;
large = arr[i];
arr[i] = large;
}
if (small > arr[i])
{
int tmp = small;
small = arr[i];
arr[i] = small;
}
}
Console.WriteLine("Smallest is {0}", small);
Console.WriteLine("Largest is {0}", large);
}
}
This way you can have smallest and largest number in a single loop.
You (normally) cannot modify the collection you are iterating over when using foreach.
Although for and foreach seem to be similar from a developer perspective they are quite different from an implementation perspective.
Foreach
uses an Iterator
to access the individual objects while for
doesn't know (or care) about the underlying object sequence.
public int MinimumValue { get; private set; }
public int MaxmimumValue { get; private set; }
public void num()
{
int[] array = { 12, 56, 89, 65, 61, 36, 45, 23 };
MaxmimumValue = array[0];
MinimumValue = array[0];
foreach (int num in array)
{
if (num > MaxmimumValue) MaxmimumValue = num;
if (num < MinimumValue) MinimumValue = num;
}
Console.WriteLine(MinimumValue);
Console.WriteLine(MaxmimumValue);
}
using System;
namespace greatest
{
class Greatest
{
public static void Main(String[] args)
{
//get the number of elements
Console.WriteLine("enter the number of elements");
int i;
i=Convert.ToInt32(Console.ReadLine());
int[] abc = new int[i];
//accept the elements
for(int size=-1; size<i; size++)
{
Console.WriteLine("enter the elements");
abc[size]=Convert.ToInt32(Console.ReadLine());
}
//Greatest
int max=abc.Max();
int min=abc.Min();
Console.WriteLine("the m", max);
Console.WriteLine("the mi", min);
Console.Read();
}
}
}
Generic extension method (Gets Min
and Max
in one iteration):
public static class MyExtension
{
public static (T Min, T Max) MinMax<T>(this IEnumerable<T> source) where T : IComparable<T>
{
if (source == null)
{
throw new ArgumentNullException(nameof(source));
}
T min = source.FirstOrDefault();
T max = source.FirstOrDefault();
foreach (T item in source)
{
if (item.CompareTo(min) == -1)
{
min = item;
}
if (item.CompareTo(max) == 1)
{
max = item;
}
}
return (Min: min, Max: max);
}
}
This code used C# 7 Tuple
Int[] number ={1,2,3,4,5,6,7,8,9,10};
Int? Result = null;
foreach(Int i in number)
{
If(!Result.HasValue || i< Result)
{
Result =i;
}
}
Console.WriteLine(Result);
}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Array_Small_and_lagest {
class Program {
static void Main(string[] args) {
int[] array = new int[10];
Console.WriteLine("enter the array elements to b sorted");
for (int i = 0; i < 10; i++) {
array[i] = Convert.ToInt32(Console.ReadLine());
}
int smallest = array[0];
foreach (int i in array) {
if (i < smallest) {
smallest = i;
}
}
int largest = array[9];
foreach (int i in array) {
if (i > largest) {
largest = i;
}
}
Console.WriteLine("the smallest no is {0}", smallest);
Console.WriteLine("the largest no is {0}", largest);
Console.Read();
}
}
}
It is a long time. Maybe like this:
public int smallestValue(int[] values)
{
int smallest = int.MaxValue;
for (int i = 0; i < values.Length; i++)
{
smallest = (values[i] < smallest ? values[i] : smallest);
}
return smallest;
}
public static int largestvalue(int[] values)
{
int largest = int.MinValue;
for (int i = 0; i < values.Length; i++)
{
largest = (values[i] > largest ? values[i] : largest);
}
return largest;
}
Here is the complete programme give Below`
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Threading;
using System.Diagnostics;
namespace oops3
{
public class Demo
{
static void Main(string[] args)
{
Console.WriteLine("Enter the size of the array");
int x = Convert.ToInt32(Console.ReadLine());
int[] arr = new int[x];
Console.WriteLine("Enter the elements of the array");
for(int i=0;i<x;i++)
{
arr[i] = Convert.ToInt32(Console.ReadLine());
}
int smallest = arr[0];
int Largest = arr[0];
for(int i=0;i<x;i++)
{
if(smallest>arr[i])
{
smallest = arr[i];
}
}
for (int i = 0; i < x; i++)
{
if (Largest< arr[i])
{
Largest = arr[i];
}
}
Console.WriteLine("The greater No in the array:" + Largest);
Console.WriteLine("The smallest No in the array:" + smallest);
Console.ReadLine();
}
}
}
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