Regex with lookahead

I can't seem to make this regex work.

The input is as follows. Its really on one row but I have inserted line brea开发者_如何学JAVAks after each \r\n so that it's easier to see, so no check for space characters are needed.

01-03\r\n
01-04\r\n
TEXTONE\r\n
STOCKHOLM\r\n
350,00\r\n            ---- 350,00 should be the last value in the first match
12-29\r\n
01-03\r\n
TEXTTWO\r\n
COPENHAGEN\r\n
10,80\r\n

This could go on with another 01-31 and 02-01, marking another new match (these are dates).

I would like to have a total of 2 matches for this input. My problem is that I cant figure out how to look ahead and match the starting of a new match (two following dates) but not to include those dates within the first match. They should belong to the second match.

It's hard to explain, but I hope someone will get me. This is what I got so far but its not even close:

(.*?)((?<=\\d{2}-\\d{2}))

The matches I want are:

1: 01-03\r\n01-04\r\nTEXTONE\r\nSTOCKHOLM\r\n350,00\r\n
2: 12-29\r\n01-03\r\nTEXTTWO\r\nCOPENHAGEN\r\n10,80\r\n

After that I can easily separate the columns with \r\n.

Can this more explicit pattern work to you?

(\d{2}-\d{2})\r\n(\d{2}-\d{2})\r\n(.*)\r\n(.*)\r\n(\d+(?:,?\d+))

Here's another option for you to try:

(.+?)(?=\d{2}-\d{2}\\r\\n\d{2}-\d{2}|$)

Rubular

/
   \G
   (
      (?:
         [0-9]{2}-[0-9]{2}\r\n
      ){2}
      (?:
         (?! [0-9]{2}-[0-9]{2}\r\n ) [^\n]*\n
      )*
   )
/xg

Why do so much work?

$string = q(01-03\r\n01-04\r\nTEXTONE\r\nSTOCKHOLM\r\n350,00\r\n12-29\r\n01-03\r\nTEXTTWO\r\nCOPENHAGEN\r\n10,80\r\n);
for (split /(?=(?:\d{2}-\d{2}\\r\\n){2})/, $string) {
   print join( "\t", split /\\r\\n/), "\n"
}

Output:

01-03   01-04   TEXTONE STOCKHOLM       350,00
12-29   01-03   TEXTTWO COPENHAGEN      10,80`