Patching bean config XML file dynamically using sed?
I have a bean configuration XML file which looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<beans>
<bean id="myDataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName">
<value>MyDriver</value>
</property>
<property name="url">
<value>#####</value>
</property>
<property name="username">
<value>myUser</value>
</property>
<property name="password">
<value>myPassword</value>
</property>
</bean>
</beans>
I want to replace the string #####
dynamically with sed.
#####
may have different values, e.g. myUrl1
, myUrl2
etc. and should be replaced with another given myUrlX
So the result should be something like:
...
<property name="url">
<value>myUrlX</value>
</property>
...
So far I only got close to a solution with the following sed command:
sed -n "1h;1!H;${;g;s|\(<property [^>]*>.*<value>\).*\(</value>.*</property>\)|\1myUrl\2|g;p;}" test.xml
But this replaces the myPassw开发者_StackOverflow社区ord
string in my XML file instead of #####
.
Could anyone give me a hint what I need to change in my sed command?
Thanks a lot!
Use xmlstarlet:
xml ed --update "/beans/bean[@id='myDataSource']/property[@name='url']/value" --value myUrlX inputfile.xml
To query:
xml sel -t -m "/beans/bean[@id='myDataSource']/property[@name='url']" -v value inputfile.xml
Put them together:
#!/bin/bash
file=inputfile.xml
val=$(xml sel -t -m "/beans/bean[@id='myDataSource']/property[@name='url']" -v value "$file")
if [[ $val == "foo" ]]
then
val=bar
xml ed --update "/beans/bean[@id='myDataSource']/property[@name='url']/value" --value "$val" "$file"
fi
On my system, the command is xmlstarlet
instead of xml
.
Don't use regexes.
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